Question

The oxidation potential of a hydrogen electrode at pH = 10 and $P_{H_2}=1$ atm

• A. 0.059 V
• B. 0.59 V
• C. 0.00 V
• D. 0.51 V

Answer 1

Answer: (B)

$E_{OP}=E_{OP}^o-\frac{0.059}{1}log\frac{[H^{+}]}{P_{H_2}}$
So $[H^{+}]=10^{-10}$
$P_{H_2}=1$ atm, $E_{OP}=0.59$ V