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Q. The oxidation potential of a hydrogen electrode at pH = 10 and $P_{H_{2}}=1$ atm

NTA AbhyasNTA Abhyas 2022

Solution:

$E_{O P}=E_{O P}^{o}-\frac{0.059}{1}log\frac{\left[\right. H^{+} \left]\right.}{P_{H_{2}}}$
So $\left[\right.H^{+}\left]\right.=10^{- 10}$
$P_{H_{2}}=1$ atm, $E_{O P}=0.59$ V