Question

The oxidation numbers of hydrogen in $KH,Mg{H}_2$ and NaH are respectively

• A. $+2,+1$ and $-2$
• B. $+1,+1$ and $+1$
• C. $-1,-1$ and $-1$
• D. $-2,-3$ and $-1$

Answer 1

Answer: (C)

Hydrogen is present as hydride ion in these mole cules i.e., oxidation state is $-1$.