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Chemistry
The oxidation numbers of hydrogen in KH , MgH 2 and NaH are respectively
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Q. The oxidation numbers of hydrogen in $KH , MgH _{2}$ and NaH are respectively
Redox Reactions
A
$+2,+1$ and $-2$
1%
B
$+1,+1$ and $ +1 $
9%
C
$-1,-1 $ and $-1$
88%
D
$-2,-3$ and $-1$
1%
Solution:
Hydrogen is present as hydride ion in these mole cules i.e., oxidation state is $- 1$.