The oxidation number of sulphur in S8, S2F2, H2S respectively, are

Question

The oxidation number of sulphur in S8, S2F2, H2S respectively, are (A) 0, +1 and -2 (B) +2, +1 and -1 (C) 0, +1 and +2 (D) -2, +1 and -2

Tardigrade Admin · Accepted Answer

Oxidation number of S: In S8=0 (In elemental state oxidation number is zero) In oversetxS2 overset-1F2: 2 (x)+2 (-1)=0 ⇒ x=+1 In overset+1H2 oversetxS: 2 (+1) +x=0 ⇒ x=-2

Q. The oxidation number of sulphur in $S_{8}, S_{2} F_{2}, H_{2} S$ respectively, are

$0, + 1$ and $- 2$

$+ 2, + 1$ and $- 1$

$0, + 1$ and $+ 2$

$- 2, + 1$ and $- 2$

Oxidation number of $S$ :
In $S_{8} = 0$ (In elemental state oxidation number is zero)
In $S_{2} x F_{2} - 1 : 2 (x) + 2 (- 1) = 0$
$\Rightarrow x = + 1$
In $H_{2} + 1 S x : 2 (+ 1) + x = 0$
$\Rightarrow x = - 2$

Q. The oxidation number of sulphur in S8​,S2​F2​,H2​S respectively, are

0,+1 and −2

+2,+1 and −1

0,+1 and +2

−2,+1 and −2