Question

The oxidation number of sulphur in $S_{8}, S_{2}F_{2}, H_{2}S$ respectively, are

• A. $0, +1$ and $-2$
• B. $+2, +1$ and $-1$
• C. $0, +1 $ and $+2$
• D. $-2, +1$ and $-2$

Answer 1

Answer: (A)

Oxidation number of $S$ :
In $S_{8}=0$ (In elemental state oxidation number is zero)
In $\overset{x}{S_{2}} \overset{-1}{F_{2}} : 2 (x)+2 (-1)=0$
$\Rightarrow x=+1$
In $\overset{+1}{H_{2}} \overset{x}{S} : 2 (+1) +x=0$
$\Rightarrow x=-2$