The oxidation number of sulphur in H2SO4, H2S2O4 and H2S2O6 are respectively

Question

The oxidation number of sulphur in H2SO4, H2S2O4 and H2S2O6 are respectively (A) +3, +4, +5 (B) +5, +4, +3 (C) +6, +3, + 5 (D) +3, +5, +4

Tardigrade Admin · Accepted Answer

O.N. of S in H2SO4: Let O.N. of S = x .-. 2 (+ 1) + x + 4(-2) = 0 ⇒ x=+6 O.N. of S in H2S2O4 Let O.N. of S = x =2(4-1) + l x + 4(-2) = 0 ⇒ x=+3 O.N. of S in H2S2O 6 Let O.N. of S = x 2(4-1) + 2x + 6(-2) = 0 ⇒ x=+5

Q. The oxidation number of sulphur in $H_{2} S O_{4}, H_{2} S_{2} O_{4} an d H_{2} S_{2} O_{6}$ are respectively

+3, +4, +5

+5, +4, +3

+6, +3, + 5

+3, +5, +4

O.N. of S in $H_{2} S O_{4}$ :
Let O.N. of S = x
.-. 2 (+ 1) + x + 4(-2) = 0
$\Rightarrow x = + 6$
O.N. of S in $H_{2} S_{2} O_{4}$
Let O.N. of S = x
=2(4-1) + l x + 4(-2) = 0
$\Rightarrow x = + 3$
O.N. of S in $H_{2} S_{2} O_{6}$
Let O.N. of S = x
2(4-1) + 2x + 6(-2) = 0
$\Rightarrow x = + 5$

Q. The oxidation number of sulphur in H2​SO4​,H2​S2​O4​andH2​S2​O6​ are respectively