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Q. The oxidation number of sulphur in $H_2SO_4, H_2S_2O_4 \, and \, H_2S_2O_6$ are respectively

Redox Reactions

Solution:

O.N. of S in $H_2SO_4$:
Let O.N. of S = x
.-. 2 (+ 1) + x + 4(-2) = 0
$\Rightarrow x=+6$
O.N. of S in $H_2S_2O_4$
Let O.N. of S = x
=2(4-1) + l x + 4(-2) = 0
$\Rightarrow x=+3$
O.N. of S in $H_2S_2O_ 6$
Let O.N. of S = x
2(4-1) + 2x + 6(-2) = 0
$\Rightarrow x=+5$