The oxidation number of sulphur in dithionous acid is.

Question

The oxidation number of sulphur in dithionous acid is. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

The structure of dithionous acid ( H 2 S 2 O 4) is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/d64b3dad39d1bff6fe9f39bb81890ef2-.png" /> Hence, +1 × 2)+2 x+(-2 × 4)=0 ∴ 2 x+2-8=0 ∴ x=+3

Q. The oxidation number of sulphur in dithionous acid is_______.

The structure of dithionous acid $(H_{2} S_{2} O_{4})$ is

Hence, $+ 1 \times 2) + 2 x + (- 2 \times 4) = 0$
$∴ 2 x + 2 - 8 = 0$
$∴ x = + 3$

Q. The oxidation number of sulphur in dithionous acid is_______.

The structure of dithionous acid (H2​S2​O4​) is Hence, +1×2)+2x+(−2×4)=0 ∴2x+2−8=0 ∴x=+3

The structure of dithionous acid $(H_{2} S_{2} O_{4})$ is

Hence, $+ 1 \times 2) + 2 x + (- 2 \times 4) = 0$
$∴ 2 x + 2 - 8 = 0$
$∴ x = + 3$