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Q.
The oxidation number of sulphur in dithionous acid is_______.
The p-Block Elements - Part2
Solution:
The structure of dithionous acid $\left( H _{2} S _{2} O _{4}\right)$ is
Hence, $+1 \times 2)+2 x+(-2 \times 4)=0$
$\therefore 2 x+2-8=0$
$\therefore x=+3$
