The oxidation number of S in H2S4O6 is

Question

The oxidation number of S in H2S4O6 is (A) + 8/3 (B) + 5/2 (C) +5 (D) -1

Tardigrade Admin · Accepted Answer

The structure of H2S4O6 is shown below: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/346c9aa717d14e24828c0434a2191315-.png" /> The O.N. of each of the S atoms linked with each other in the middle is zero while that of each of the remaining two S-atoms is +5. Thus, the average oxidation number of S=(+5+0+0+5/4) =+ (5/2)

Q. The oxidation number of $S$ in $H_{2} S_{4} O_{6}$ is

$+ 8/3$

$+ 5/2$

$+ 5$

$- 1$

The structure of $H_{2} S_{4} O_{6}$ is shown below:

The O.N. of each of the S atoms linked with each other in the middle is zero while that of each of the remaining two S-atoms is +5. Thus, the average oxidation number of
$S = \frac{+ 5 + 0 + 0 + 5}{4}$
$= + \frac{5}{2}$

Q. The oxidation number of S in H2​S4​O6​ is

+8/3

+5/2

+5

−1