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Q.
The oxidation number of $S$ in $H_{2}S_{4}O_{6}$ is
Redox Reactions
Solution:
The structure of $H_{2}S_{4}O_{6}$ is shown below:
The O.N. of each of the S atoms linked with each other in the middle is zero while that of each of the remaining two S-atoms is +5. Thus, the average oxidation number of
$S=\frac{+5+0+0+5}{4}$
$=+ \frac{5}{2}$
