Question

The oxidation number of phosphorus in $Ba(H_{2}P{O}_2{)}_2$ is

• A. $+1$
• B. $-1$
• C. $+2$
• D. $+3$

Answer 1

Answer: (A)

$Ba(H_2\stackrel{\ast }{P}O-2{)}_2;Ba{H}_4\stackrel{\ast }{P_2}{O}_4$
$2+4+2x-8=0;2x=2$
$x=\frac{2}{2}=+1.$