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  4. The oxidation number of phosphorus in Ba(H2PO2)2 is

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Q. The oxidation number of phosphorus in $Ba(H_{2}PO_{2})_{2}$ is

Redox Reactions

Solution:

$Ba(H_{2}\overset{*}{P}O-{2})_{2}; BaH_{4} \overset{*}{P_{2}}O_{4}$
$2 + 4 + 2x- 8 = 0; 2x = 2$
$x=\frac{2}{2}=+1.$