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Tardigrade
Question
Chemistry
The oxidation number of oxygen in KO 3, Na 2 O 2 is
Q. The oxidation number of oxygen in
K
O
3
,
N
a
2
O
2
is
2836
217
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A
3, 2
B
1, 0
C
0, 1
D
-0.33, -1
Solution:
K
O
3
Suppose O.N. of
O
=
x
+
1
+
3
x
=
0
3
x
=
−
1
x
=
−
3
1
x
=
−
0.33
N
a
2
O
2
Suppose O.N. of
O
=
x
2
×
1
+
2
x
=
0
2
+
2
x
=
0
2
x
=
−
2
x
=
−
2
2
x
=
−
1