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Q. The oxidation number of oxygen in $KO _{3}, Na _{2} O _{2}$ is

VITEEEVITEEE 2008

Solution:

$KO _{3}$
Suppose O.N. of $O =x$
$+1+3 x =0 $
$3 x =-1 $
$x =-\frac{1}{3} $
$x =-0.33$

$Na _{2} O _{2}$
Suppose O.N. of $O =x$
$2 \times 1+2 x=0$
$2+2 x=0$
$2 x=-2$
$x=-\frac{2}{2}$
$x=-1$