Question

The oxidation number of $N$ and $Cl$ in $NOCl{O}_4$ respectively are

• A. +2 and +7
• B. +3 and +7
• C. -3 and +7
• D. +2 and -7

Answer 1

Answer: (B)

Oxidation number of $N$ in $N{O}^{+}$ is $(1\times x)+1\times (-2)=+1$ $x=+3$ Oxidation number of $Cl$ in $Cl{O}_4^{-}$ is $(1\times x)+4\times (-2)=-1$ $\therefore$ $x=+7$