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  4. The oxidation number of N and Cl in NOClO4 respectively are

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Q. The oxidation number of $ N $ and $ Cl $ in $ NOCl{{O}_{4}} $ respectively are

CMC MedicalCMC Medical 2014

Solution:

Oxidation number of $ N $ in $ N{{O}^{+}} $ is $ (1\times x)+1\times (-2)=+1 $ $ x=+\,3 $ Oxidation number of $ Cl $ in $ ClO_{4}^{-} $ is $ (1\times x)+4\times (-2)=-1 $ $ \therefore $ $ x=+7 $