Q. The oxidation number of Cr in $K_{2} C r O_{4}$ is

1747 221 Rajasthan PETRajasthan PET 2005 Report Error

A

3

B

$- 3$

C

6

D

$- 6$

Solution:

Let the oxidation number of Cr in
$R_{2} C r O_{4}$ is $x$
$2 + (1) + x + 4 (- 2) = 0$
$2 + x - 8 = 0$
$x = 8 - 2$
$= 6$