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Q. The oxidation number of Cr in $ {{K}_{2}}Cr{{O}_{4}} $ is

Rajasthan PETRajasthan PET 2005

Solution:

Let the oxidation number of Cr in
$ {{R}_{2}}Cr{{O}_{4}} $ is $ x $
$ 2+(1)+x+4(-2)=0 $
$ 2+x-8=0 $
$ x=8-2 $
$ =6 $