Question

The oxidation number of chromium in potassium dichromate $(K_{2}C{r}_2{O}_7)$ , is

• A. $+2$
• B. $+6$
• C. $+4$
• D. $+8$

Answer 1

Answer: (B)

Let x be the oxidation number of chromium in $K_{2}C{r}_2{O}_7$ . Therefore, $(2\times 1)+2x+7(-2)=0$ or $2+2x-14=0$ or $x=+6$