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Q. The oxidation number of chromium in potassium dichromate $ ({{K}_{2}}C{{r}_{2}}{{O}_{7}}) $ , is

Punjab PMETPunjab PMET 1999

Solution:

Let x be the oxidation number of chromium in $ {{K}_{2}}C{{r}_{2}}{{O}_{7}} $ . Therefore, $ (2\times 1)+2x+7(-2)=0 $ or $ 2+2x-14=0 $ or $ x=+6 $