Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The oxidation number of carbon in CH2O is
Q. The oxidation number of carbon in
C
H
2
O
is
1768
227
Redox Reactions
Report Error
A
-2
4%
B
+2
13%
C
0
71%
D
+4
11%
Solution:
Let the oxidation state of C in
C
H
2
O
be x, then we have,
x
+
2
+
(
−
2
)
=
0
or
x
=
0