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Chemistry
The oxidation number of carbon in CH2O is
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Q. The oxidation number of carbon in $CH_2O$ is
Redox Reactions
A
-2
4%
B
+2
13%
C
0
71%
D
+4
11%
Solution:
Let the oxidation state of C in $CH_2O$ be x, then we have, $x + 2 + (-2) = 0$ or $x = 0$