Question

The oxidation number of C in sucrose $(C_{12}{H}_{22}{O}_{11})$ is

• A. +4
• B. +3
• C. +2
• D. 0

Answer 1

Answer: (D)

$\stackrel{x}{C_{12}}\stackrel{+1}{H_{22}}\stackrel{-2}{O_{11}}$
So, $12\text{x}+22(+1)+11(-2)=0$
or $x=0$