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  4. The oxidation number of C in sucrose (.C12H22O11.) is

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Q. The oxidation number of C in sucrose $\left(\right.C_{12}H_{22}O_{11}\left.\right)$ is

NTA AbhyasNTA Abhyas 2022

Solution:

$\overset{x}{C_{12}}\overset{+ 1}{H_{22}}\overset{- 2}{O_{11}}$
So, $12 \text{x} + 22 \left(\right. + 1 \left.\right) + 11 \left(\right. - 2 \left.\right) = 0$
or $x=0$