The oxidation number of C in CH4, CH3Cl. CH2Cl2, CHCl3 and CCl4 is respectively

Question

The oxidation number of C in CH4, CH3Cl. CH2Cl2, CHCl3 and CCl4 is respectively (A) 4, - 2, 0, + 2, + 4 (B) + 2, 4, 0, - 2, - 4 (C) 4, 2, 0, - 2, - 4 (D) 0, 2, - 2, 4, 4

Tardigrade Admin · Accepted Answer

CH4; x+4(-1) = 0 or x = +4H3C1; x + 3( + 1) + (-1)= 0 or x = -2CH2C12 given in Q-6CHC13;x + 1 + 3(-1) = 0 or x = + 2CCIt4; x + 4(-1) = 0 or x = +4.

Q. The oxidation number of C in $C H_{4}, C H_{3} Cl . C H_{2} C l_{2}, C H C l_{3} an d CC l_{4}$ is respectively

4, - 2, 0, + 2, + 4

+ 2, 4, 0, - 2, - 4

4, 2, 0, - 2, - 4

0, 2, - 2, 4, 4

$C H_{4}; x + 4 (- 1) = 0 or x = + 4$ $H_{3} C 1; x + 3 (+ 1) + (- 1) = 0 or x = - 2$ $C H_{2} C 1_{2}$ given in Q-6 $C H C 1_{3}$ ;x + 1 + 3(-1) = 0 or x = + 2 $CC I_{t} 4$ ; x + 4(-1) = 0 or x = +4.

Q. The oxidation number of C in CH4​,CH3​Cl.CH2​Cl2​,CHCl3​andCCl4​ is respectively