1. Tardigrade
  2. Question
  3. Chemistry
  4. The oxidation number of C in CH4, CH3Cl. CH2Cl2, CHCl3 and CCl4 is respectively

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The oxidation number of C in $CH_4, CH_3Cl. CH_2Cl_2, CHCl_3 \,and \,CCl_4$ is respectively

Redox Reactions

Solution:

$CH_4; x+4(-1) = 0 \,or \,x = +4$$H_3C1; x + 3( + 1) + (-1)= 0 \,or\,x = -2$$CH_2C1_2$ given in Q-6$CHC1_3$;x + 1 + 3(-1) = 0 or x = + 2$CCI_t4$; x + 4(-1) = 0 or x = +4.