Question

The oxidation number of C-atom in $C{H}_{2}C{l}_2$ and $CC{l}_4$ is respectively

• A. zero and 4
• B. zero and -4
• C. 2 and 4
• D. -2 and -4

Answer 1

Answer: (A)

Let the oxidation state of C in $C{H}_{2}C{l}_2$ is $x$ . $x+2+2(-1)=0$ $x+2-2=0$ $x=0$ Let the oxidation state of C in $CC{l}_4$ is $x$ $x+4(x-1)=0$ $x-4=0$ $x=+4$ Hence, the oxidation number of C-atom in $C{H}_{2}C{l}_2$ and $CC{l}_4$ are zero and +4 respectively.