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  4. The oxidation number of C-atom in CH2Cl2 and CCl4 is respectively

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Q. The oxidation number of C-atom in $ C{{H}_{2}}C{{l}_{2}} $ and $ CC{{l}_{4}} $ is respectively

Rajasthan PETRajasthan PET 2005

Solution:

Let the oxidation state of C in $ C{{H}_{2}}C{{l}_{2}} $ is $ x $ . $ x+2+2(-1)=0 $ $ x+2-2=0 $ $ x=0 $ Let the oxidation state of C in $ CC{{l}_{4}} $ is $ x $ $ x+4(x-1)=0 $ $ x-4=0 $ $ x=+4 $ Hence, the oxidation number of C-atom in $ C{{H}_{2}}C{{l}_{2}} $ and $ CC{{l}_{4}} $ are zero and +4 respectively.