The osmotic pressure of a 5% (wt./vol) solution of cane sugar at 150 oC is

Question

The osmotic pressure of a 5% (wt./vol) solution of cane sugar at 150 oC is (A)  text ! !~ ! ! text 3 text.078 atm  (B)  text4 text.078 atm  (C)  5.078 textatm  (D)  2.45 textatm

Tardigrade Admin · Accepted Answer

C=(5/342)× (1/100)× 1000 textC text=( text50/ text342) textmol/L π text= CRT=(50/342)× 0.082× 423=5.07 textatm

Q. The osmotic pressure of a 5% (wt./vol) solution of cane sugar at $150^{o} C$ is

$3 .078 atm$

$4 .078 atm$

$5.078 atm$

$2.45 atm$

$C = \frac{5}{342} \times \frac{1}{100} \times 1000$
$C = \frac{50}{342} mol/L$
$π = CRT= \frac{50}{342} \times 0.082 \times 423 = 5.07 atm$

Q. The osmotic pressure of a 5% (wt./vol) solution of cane sugar at 150oC is

3.078 atm

4.078 atm

5.078atm

2.45atm