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Q. The osmotic pressure of a 5% (wt./vol) solution of cane sugar at $ 150{{\,}^{o}}C $ is

Jharkhand CECEJharkhand CECE 2015

Solution:

$ C=\frac{5}{342}\times \frac{1}{100}\times 1000 $
$ \text{C}\,\text{=}\frac{\text{50}}{\text{342}}\text{mol/L} $
$ \pi \,\text{= CRT=}\frac{50}{342}\times 0.082\times 423=5.07\,\text{atm} $