The osmotic pressure exerted by a solution prepared by dissolving 2.0 g of protein of molar mass 60 kg mol -1 in 200 mL of water at 27° C is Pa. [integer value] (use R =0.083 L bar mol -1 K -1 )

Question

The osmotic pressure exerted by a solution prepared by dissolving 2.0 g of protein of molar mass 60 kg mol -1 in 200 mL of water at 27° C is Pa. [integer value] (use R =0.083 L bar mol -1 K -1 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

π= iCRT =(1 × 2/60000 × 0.2) × 0.083 × 300 =0.00415 bar ( 1. bar .=105 Pa ) So, 0.00415 × 105 Pa =415 Pa

Q. The osmotic pressure exerted by a solution prepared by dissolving $2.0 g$ of protein of molar mass $60 k g m o l^{- 1}$ in $200 m L$ of water at $2 7^{\circ} C$ is ____ $P a$ . [integer value]
(use $R = 0.083 L$ bar $m o l^{- 1} K^{- 1}$ )

$π = i CRT$
$= \frac{1 \times 2}{60000 \times 0.2} \times 0.083 \times 300$
$= 0.00415$ bar $(1$ bar $= 1 0^{5} P a)$
So, $0.00415 \times 1 0^{5} P a = 415 P a$

Q. The osmotic pressure exerted by a solution prepared by dissolving 2.0g of protein of molar mass 60kgmol−1 in 200mL of water at 27∘C is ____Pa. [integer value] (use R=0.083L bar mol−1K−1 )

π=iCRT =60000×0.21×2​×0.083×300 =0.00415 bar (1 bar =105Pa) So, 0.00415×105Pa=415Pa

Q. The osmotic pressure exerted by a solution prepared by dissolving $2.0 g$ of protein of molar mass $60 k g m o l^{- 1}$ in $200 m L$ of water at $2 7^{\circ} C$ is ____ $P a$ . [integer value]
(use $R = 0.083 L$ bar $m o l^{- 1} K^{- 1}$ )

$π = i CRT$
$= \frac{1 \times 2}{60000 \times 0.2} \times 0.083 \times 300$
$= 0.00415$ bar $(1$ bar $= 1 0^{5} P a)$
So, $0.00415 \times 1 0^{5} P a = 415 P a$