Question

The osmotic pressure exerted by a solution prepared by dissolving $2.0 \,g$ of protein of molar mass $60 \, kg \, mol ^{-1}$ in $200 \, mL$ of water at $27^{\circ} C$ is ____$Pa$. [integer value]
(use $R =0.083 \,L$ bar $mol ^{-1} \,K ^{-1}$ )

Answer 1

$\pi= iCRT$
$=\frac{1 \times 2}{60000 \times 0.2} \times 0.083 \times 300$
$=0.00415$ bar $\left( 1\right.$ bar $\left.=10^{5} Pa \right)$
So, $0.00415 \times 10^{5} \,Pa =415\, Pa$