The order of the differential equation obtained by eliminating arbitrary constants in the family of curves c1y = (c2 +c3 )ex+c4 is

Question

The order of the differential equation obtained by eliminating arbitrary constants in the family of curves c1y = (c2 +c3 )ex+c4 is (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

(y = [((C2 + C3/C1))eC4]ex = A ex,) where A = (((C2 + C3/C1))eC4) Order = Number of independent arbitrary constants = 1

Q. The order of the differential equation obtained by eliminating arbitrary constants in the family of curves $c_{1} y = (c_{2} + c_{3}) e^{x + c_{4}}$ is

1

2

3

4

$(y = [(\frac{C _{2} + C _{3}}{C _{1}}) e^{C_{4}}] e^{x} = A e^{x},)$
where $A = ((\frac{C _{2} + C _{3}}{C _{1}}) e^{C_{4}})$
Order = Number of independent arbitrary constants $= 1$

Q. The order of the differential equation obtained by eliminating arbitrary constants in the family of curves c1​y=(c2​+c3​)ex+c4​ is

1

2

3

4

(y=[(C1​C2​+C3​​)eC4​]ex=Aex,) where A=((C1​C2​+C3​​)eC4​) Order = Number of independent arbitrary constants =1

Q. The order of the differential equation obtained by eliminating arbitrary constants in the family of curves $c_{1} y = (c_{2} + c_{3}) e^{x + c_{4}}$ is

$(y = [(\frac{C _{2} + C _{3}}{C _{1}}) e^{C_{4}}] e^{x} = A e^{x},)$
where $A = ((\frac{C _{2} + C _{3}}{C _{1}}) e^{C_{4}})$
Order = Number of independent arbitrary constants $= 1$