The order of ka values of the following acids is :-

Question

The order of ka values of the following acids is :- <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-zxk96uy7fees.png" /> (A) (i) > (iv) > (iii) > (iv) (B) (iv) > (i) > (iii) > (ii) (C) (iii) > (iv) > (i) > (ii) (D) (iv) > (i) > (ii) > (iii)

Tardigrade Admin · Accepted Answer

textKa propto textAcidity text(iv) is most acidic as its conjugate base is stabilized by the two - textOH groups by intra-molecular textH -bonding. text(ii) is least acidic as conjugate base is not stabiilized by textH -bond.

Q. The order of ka values of the following acids is :-

(i) > (iv) > (iii) > (iv)

(iv) > (i) > (iii) > (ii)

(iii) > (iv) > (i) > (ii)

(iv) > (i) > (ii) > (iii)

$Ka \propto Acidity$

$(iv)$ is most acidic as its conjugate base is stabilized by the two $- OH$ groups by intra-molecular $H$ -bonding.

$(ii)$ is least acidic as conjugate base is not stabiilized by $H$ -bond.

Q. The order of ka values of the following acids is :-

(i) > (iv) > (iii) > (iv)

(iv) > (i) > (iii) > (ii)

(iii) > (iv) > (i) > (ii)

(iv) > (i) > (ii) > (iii)

Ka∝Acidity (iv) is most acidic as its conjugate base is stabilized by the two −OH groups by intra-molecular H -bonding. (ii) is least acidic as conjugate base is not stabiilized by H -bond.

$Ka \propto Acidity$

$(iv)$ is most acidic as its conjugate base is stabilized by the two $- OH$ groups by intra-molecular $H$ -bonding.

$(ii)$ is least acidic as conjugate base is not stabiilized by $H$ -bond.