Question

The orbital angular momentum of a p-electron is given as -

• A. $\sqrt{3}\frac{h}{2\pi }$
• B. $\sqrt{3}2\frac{h}{\pi }$
• C. $\sqrt{6}\sqrt{\frac{h}{2\pi }}$
• D. $\frac{h}{\sqrt{2}\pi }$

Answer 1

Answer: (D)

Orbital angular momentum $=\sqrt{l(l+1)}\times \frac{h}{2\pi }$
$\because$ For p-electron, $l=1$
$\therefore$ Orbital angular momentum,
$=\sqrt{1(1+1)}\times \frac{h}{2\pi }$
$=\sqrt{2}\times \frac{h}{2\pi }$
$=\frac{h}{\sqrt{2}\pi }$