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Q. The orbital angular momentum of a p-electron is given as -

AIPMTAIPMT 2012Structure of Atom

Solution:

Orbital angular momentum $=\sqrt{l(l+1)}\times \frac{h}{2\pi } $
$ \because $ For p-electron, $l=1$
$ \therefore $ Orbital angular momentum,
$=\sqrt{1(1+1)}\times \frac{h}{2\pi }$
$=\sqrt{2}\times \frac{h}{2\pi }$
$=\frac{h}{\sqrt{2}\pi }$