The optical path difference is defined as Δ x=(2π /λ ). what are dimensions of optical path difference?

Question

The optical path difference is defined as Δ x=(2π /λ ). what are dimensions of optical path difference? (A)  M0L-1T0  (B)  [M1L-1T0]  (C)  [ML0T2]  (D)  [ML-2T]

Tardigrade Admin · Accepted Answer

Δ x=(2π /λ ) [Δ x]=[ (2π /λ ) ]=[ (1/L) ]=[L-1] =[M0L-1T0]

Q. The optical path difference is defined as $Δ x = \frac{2 π}{λ} .$ what are dimensions of optical path difference?

$M^{0} L^{- 1} T^{0}$

$[M^{1} L^{- 1} T^{0}]$

$[M L^{0} T^{2}]$

$[M L^{- 2} T]$

$Δ x = \frac{2 π}{λ}$ $[Δ x] = [\frac{2 π}{λ}] = [\frac{1}{L}] = [L^{- 1}]$ $= [M^{0} L^{- 1} T^{0}]$

Q. The optical path difference is defined as Δx=λ2π​. what are dimensions of optical path difference?

M0L−1T0

[M1L−1T0]

[ML0T2]

[ML−2T]