Question

The optical path difference is defined as $ \Delta x=\frac{2\pi }{\lambda }. $ what are dimensions of optical path difference?

• A. $ {{M}^{0}}{{L}^{-1}}{{T}^{0}} $
• B. $ [{{M}^{1}}{{L}^{-1}}{{T}^{0}}] $
• C. $ [M{{L}^{0}}{{T}^{2}}] $
• D. $ [M{{L}^{-2}}T] $

Answer 1

Answer: (A)

$ \Delta x=\frac{2\pi }{\lambda } $ $ [\Delta x]=\left[ \frac{2\pi }{\lambda } \right]=\left[ \frac{1}{L} \right]=[{{L}^{-1}}] $ $ =[{{M}^{0}}{{L}^{-1}}{{T}^{0}}] $