Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The open-chain glucose on oxidation with HIO4 gives
Q. The open-chain glucose on oxidation with
H
I
O
4
gives
48
145
NTA Abhyas
NTA Abhyas 2022
Report Error
A
5
H
COO
H
+
H
2
C
=
O
B
4
H
COO
H
+
2
H
2
C
=
O
C
3
H
COO
H
+
3
H
2
C
=
O
D
2
H
COO
H
+
4
H
2
C
=
O
Solution:
Both -CHO(aldehydic) group and -RCHOH(Secondary alcoholic) group form HCOOH on reaction with HIO
4
while
−
C
H
2
O
H
(primary alcoholic) group forms
H
2
C
=
O
(fromaldehyde)
