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  4. The open-chain glucose on oxidation with HIO4 gives

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Q. The open-chain glucose on oxidation with $HIO_{4}$ gives

NTA AbhyasNTA Abhyas 2022

Solution:

Both -CHO(aldehydic) group and -RCHOH(Secondary alcoholic) group form HCOOH on reaction with HIO4 while $-CH_{2}OH$ (primary alcoholic) group forms $H_{2}C=O$ (fromaldehyde)
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