The open-chain glucose on oxidation with HIO4 gives

Question

The open-chain glucose on oxidation with HIO4 gives (A) 5HCOOH+H2C=O (B) 4HCOOH+2H2C=O (C) 3HCOOH+3H2C=O (D) 2HCOOH+4H2C=O

Tardigrade Admin · Accepted Answer

Both CHO and CHOH form HCOOH; while HOCH2 forms H2C=O giving 5HCOOH+H2C=O . <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-scho1okleabw.png" />

Q. The open-chain glucose on oxidation with $H I O_{4}$ gives

$5 H COO H + H_{2} C = O$

$4 H COO H + 2 H_{2} C = O$

$3 H COO H + 3 H_{2} C = O$

$2 H COO H + 4 H_{2} C = O$

Both CHO and CHOH form HCOOH; while $H OC H_{2}$ forms $H_{2} C = O$ giving $5 H COO H + H_{2} C = O$ .

Q. The open-chain glucose on oxidation with HIO4​ gives

5HCOOH+H2​C=O

4HCOOH+2H2​C=O

3HCOOH+3H2​C=O

2HCOOH+4H2​C=O