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  4. The open-chain glucose on oxidation with HIO4 gives

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Q. The open-chain glucose on oxidation with $HIO_{4}$ gives

NTA AbhyasNTA Abhyas 2020Biomolecules

Solution:

Both CHO and CHOH form HCOOH; while $HOCH_{2}$ forms $H_{2}C=O$ giving $5HCOOH+H_{2}C=O$ .

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