Question

The number of possible alcohol isomers for $C_4{H}_{10}O$ is

• A. $4$
• B. $3$
• C. $2$
• D. $5$

Answer 1

Answer: (A)

Possible alcohol isomers of $C_4{H}_{10}O$ is $4$.
(i) $C{H}_{3}C{H}_{2}C{H}_{2}OH$
$1$-butanol ($n$-butyl alcohol)
(ii) $C{H}_{3}C{H}_2-\underset{\stackrel{|}{O}H}{C}H-C{H}_3$
$2$-butanol (sec-butyl alcohol)
(iii) $(C{H}_3{)}_{2}CHC{H}_{2}OH$
$2$-methyl-l-propanol (iso-butyl alcohol)

$2$-methyl-$2$-propanol (t-butyl alcohol)