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Chemistry
The number of possible alcohol isomers for C4H10O is
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Q. The number of possible alcohol isomers for $ C_4H_{10}O $ is
AMU
AMU 2015
Alcohols Phenols and Ethers
A
$ 4 $
56%
B
$ 3 $
11%
C
$ 2 $
8%
D
$ 5 $
25%
Solution:
Possible alcohol isomers of $C_4 H_{10}O$ is $4$.
(i) $CH_3CH_2CH_2OH$
$1$-butanol ($n$-butyl alcohol)
(ii) $CH_3CH_2 - \underset{\overset{|}{O}{H}}{C} H - CH_3$
$2$-butanol (sec-butyl alcohol)
(iii) $(CH_3)_2 CHCH_2OH$
$2$-methyl-l-propanol (iso-butyl alcohol)
$2$-methyl-$2$-propanol (t-butyl alcohol)