Question

The number of points in the interval $(0,2)$ at which $f(x)=|x-0.5|+|x-1|+\tan x$ is not differentiable is

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (C)

Given, $f(x)=|x-0.5|+|x-1|+\tan x$
Clearly $f(x)$ is not differentiable at $x=0.5,1$ and $\frac{\pi }{2}$ for $x\in (0,2)$.
$\therefore$ Number of Non differentiable points of $f(x)$ are $3.$