1. Tardigrade
  2. Question
  3. Mathematics
  4. The number of points in the interval (0,2) at which f(x)=|x-0.5|+|x-1|+ tan x is not differentiable is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The number of points in the interval $(0,2)$ at which $f(x)=|x-0.5|+|x-1|+\tan x$ is not differentiable is

AP EAMCETAP EAMCET 2019

Solution:

Given, $f(x)=|x-0.5|+|x-1|+\tan x$
Clearly $f(x)$ is not differentiable at $x=0.5,1$ and $\frac{\pi}{2}$ for $x \in(0,2)$.
$\therefore $ Number of Non differentiable points of $f(x)$ are $3 .$