Question

The number of oxygen atoms in 44g $C{O}_2$ at S.T.P. is:

• A. $6.023\times {10}^{23}$
• B. $6.023\times {10}^{22}$
• C. $12.046\times {10}^{23}$
• D. none of these

Answer 1

Answer: (C)

The molecular weight of $C{O}_2=44$ $\therefore$ 44 g. $C{O}_2$ contains $C{O}_2$ molecules $=6.023\times {10}^{23}$ $\therefore$ 44 g $C{O}_2$ contains oxygen atoms $=2\times 6.023\times {10}^{23}$ $=12.046\times {10}^{23}$