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Q. The number of oxygen atoms in 44g $ C{{O}_{2}} $ at S.T.P. is:

BVP MedicalBVP Medical 2004

Solution:

The molecular weight of $ C{{O}_{2}}=44 $ $ \therefore $ 44 g. $ C{{O}_{2}} $ contains $ C{{O}_{2}} $ molecules $ =6.023\times {{10}^{23}} $ $ \therefore $ 44 g $ C{{O}_{2}} $ contains oxygen atoms $ =2\times 6.023\times {{10}^{23}} $ $ =12.046\times {{10}^{23}} $